ChessProblems.ca Originals

2011 Tourney: T41-50

Compositions:
Main Page | T1-10 | T11-20 | T21-30 | T31-40 | T51-60 | T61-70 | T71-80
HC1-10 | HC11-20 | HC21-30 | HC31-40 | HC41-50 | HC51-60 | HC61-70

Last updated: 28.10.2011
# Problem Solution
T50 Zoran Sibinović
Serbia
T50 ChessProblems.ca, 27.02.2011
B7/1Rpp4/2kqp1p1/2p3r1/3b3n/2p2p1r/1p3P2/5Knb
ser-= 95 (4+16) C+



Solution:

17.Kh6*g5 35.Kf1*g1 55.Kg4*h3 56.Kh3*h4 58.Kg5*g6 74.Kg1*h1 82.Ke4*f3 83.Kf3-e4 86.f5*e6 87.e6*d7 88.d7-d8=B 89.Bd8*c7 90.Bc7*d6 91.Bd6*c5 92.Bc5*d4 93.Bd4*c3 94.Bc3*b2 95.Bb2-a3 =

  • New ideal series-stalemate length record - last move by Bishop.
T49 Radovan Tomašević
Serbia
T49 ChessProblems.ca, 20.02.2011

ser-= 55 (3+11) C+



Solution:

1.Kh2*h1 3.Kh2*h3 10.Kc3*c4 13.Ke5*f6 22.Kc7*d8 33.Kf7*f8 44.Kc7*d7 46.Ke6*f5 47.Kf5*e4 48.Ke4*e3 49.Ke3-f4 54.e7-e8=R 55.Re8-e6 =

  • New ideal series-stalemate length record - last move by Rook.

On February 22nd Vladimír Janál and Ján Golha have published here the following improved version:
3r1n2/3b3p/5r2/5n1k/4p3/4b1pp/pp2P2P/7K
ser-= 60 (3+13) C+
1.h2*g3 3.Kh2*h3 9.Kc2*b2 10.Kb2*a2 15.Ke5*f6 24.Kc7*d8 35.Kf7*f8 37.Kg8*h7 49.Kc7*d7 51.Ke6*f5 52.Kf5*e4 53.Ke4*e3 54.Ke3-f4 59.e7-e8=R 60.Re8-e6 =
  • As of February 27th, the new ideal series-stalemate length record with last move made by Rook is 95 moves - T51 ChessProblems.ca, above!
  • Table of records: lengthrecords.chessproblems.ca.
T48 Radovan Tomašević
Serbia
T48 ChessProblems.ca, 20.02.2011

ser-h# 54 (14+2) C+



Solution:

3.Kf7*f6 5.Kg7*h8 9.Kh5*h4 11.Kh3*h2 20.Kb8*a7 36.Kb4*b5 51.Kc7*b7 53.Kc6-d5 54.Ba8-c6 c2-c4 #

  • New ideal series helpmate length record - last move by Pawn.
As of March 5th, 2011, the new record is:
Vladimír Janál
Blog zlínského problemisty, 05.03.2011
BN6/2p5/R1P2K2/N3P3/PR6/3P3P/2P1PB1Q/7k
ser-h# 75 (15+2)
T47 Zoran Sibinović & Ján Golha
Serbia & Slovakia
T47 ChessProblems.ca, 20.02.2011 (v)
B7/1R6/2k2r2/p3n1rp/1p2P3/2p1p1bn/p1K1b2p/2q5
ser-= 75 (4+15) C+



Solution:

1.Kc2*c1 4.Kb3*a2 7.Ka4*a5 8.Ka5*b4 9.Kb4*c3 11.Kd4*e3 12.Ke3*e2 23.Ke7*f6 37.Kg2*h3 52.Kf6*g5 53.Kg5*h5 69.Kg2*g3 70.Kg3*h2 73.Kf4*e5 74.Ke5-d4 75.e4-e5 =

  • New ideal series-stalemate length record - last move by Pawn.
  • Version 21.02.2011.
T46 Zoran Sibinović
Serbia
T46 ChessProblems.ca, 20.02.2011

ser-h= 33 (14+2) C+



Solution:

5.Kg7*h8 7.Kg7*f8 9.Kg7*h7 15.Kg2*f3 19.Kc4*b5 22.Ka7*b8 25.Kb6*c6 26.Kc6-d7 28.c5*d4 29.d4*e3 30.e3*f2 31.f2-f1=Q 32.Qf1*a6 33.Qa6-a8 Qa1*a8 =

  • New ideal series help-stalemate length record - last move by Queen.

On February 27th Vladimír Janál has published here the following new record:
8/7R/2K2P1N/8/B4P2/p2PP1k1/Q5P1/3NB3
ser-h= 59 (12+2) C+
4.Kf1*e1 12.Kg6*h7 14.Kg6*f6 22.Ka5*a4 39.Ke1*d1 58.Kc3*d3 59.Kd3-e4 Qa2*a3 =
T45 Zoran Sibinović & Ján Golha
Serbia & Slovakia
T45 ChessProblems.ca, 20.02.2011
B2k4/2p5/P1P1NP2/4K3/2PP3N/1R1PP2R/5P2/Q7
ser-h# 33 (15+2) C+



Solution:

8.Kg4*h3 9.Kh3*h4 15.Kc2*b3 17.Kc2*d3 18.Kd3*c4 22.Ka7*a8 25.Kb6*c6 26.Kc6-d7 28.c5*d4 29.d4*e3 30.e3*f2 31.f2-f1=B 32.Bf1*a6 33.Ba6-c8 Qa1-a4 #

  • New ideal series helpmate length record - last move by Queen.
  • Version 21.02.2011.
As of March 4th, 2011, the new record is:
Vladimír Janál
Blog zlínského problemisty, 04.03.2011
2NBN3/8/1P1PP3/2R2K2/7k/8/3P3P/1Q5B
ser-h# 47 (12+1)
T44 Zoran Sibinović
Serbia
T44 ChessProblems.ca, 20.02.2011

ser-# 60 (2+15) C+



Solution:

1.Ke1*f1 14.Ke7*f7 15.Kf7*g6 17.Kf5*g4 32.Kf1*g1 48.Kg4*h3 50.Kh2*h1 53.Kg3*f3 54.Kf3-e2 56.f4*g5 57.g5*f6 59.f7*e8=Q 60.Qe8-a4 #

  • New ideal series-mate length record - last move by Queen.

On February 26th Vladimír Janál has published here the following new record:
qKn1r3/p3b3/8/ppn5/p4pp1/p2b4/P7/1k2r3
ser-# 61 (2+15) C+
1.Kb8*a8 9.Kd2*e1 14.Ke5*f4 15.Kf4*g4 20.Kf7*e8 31.Kc7*c8 33.Kb8*a7 44.Kf7*e7 46.Kd6*c5 48.Kd4*d3 51.Kc5*b5 52.Kb5*a5 53.Ka5*a4 54.Ka4*a3 55.Ka3-b3 60.a7-a8=Q 61.Qa8-h1 #
T43 Mečislovas Rimkus
Lithuania
T43 ChessProblems.ca, 07.02.2011

ser-h# 12* (9+7) C+
Grasshopper f5, g8


Set play:
1...Gf5*d7 # 

Solution:
1.e6*f5 2.f5-f4 3.f4*g3 4.g3*h2 5.h2-h1=G 6.Gh1-e1 7.Ge1-a5 8.Ga5-d8 9.Gd8*d6 10.Gd6-d8 11.d7-d6 12.Gd8-d5 Gg8-c4 #

  • The Problem-Echo 28th TT theme.
  • Series helpmate with set play in one move (ser-h#n*), with grasshopper, nightrider, non-stop-equihopper or equihopper (at least one type, maximum two types), with at least one fairy promotion.

Václav Kotesovec and Vladislav Bunka
1st Prize, Problem-Echo 28th TT 2010

ser-h# 14* (7+9) C+
Set play: 1...Be4*d5 # #
1.d5*e4 2.e4-e3 3.e3-e2 4.e2-e1=G 5.Ge1-b4 6.Gb4-d6 7.Gc7-e5 8.Bb6-c7 9.Kc6-b6 10.Kb6*a6 11.Bc7-b6 12.Ge5-c7 13.Gd6-b4 14.Gb4-b7 Ga3-d6 #
T42 Karol Mlynka
Slovakia
T42 ChessProblems.ca, 28.01.2011

ser-h# 5 (7+1) C+
Mars Mirror Circe



Solution: 

1.Ke6*d2 2.Kd2-c3 3.Kc3-d4 4.Kd4-e5 5.Ke5-e6 Sd7-e5 #

  • Mars Mirror Circe: all units capture and check only from their Mirror Circe rebirth squares, and it may capture any such piece regardless of where it is in fact standing, provided that the rebirth square is not occupied by any other piece.
  • Mirror Circe: a captured piece is reborn on a square where a piece of the opposite color would be reborn in ordinary Circe.
T41 Karol Mlynka
Slovakia
T41 ChessProblems.ca, 24.01.2011

ser-h# 8 (5+3+1n) C+
Grasshopper b2, Neutral Pawn h7
b) CousCous Circe


Solutions: 

a) 1.nPh7*g6 2.nPg6-g5 3.nPg5-g4 4.nPg4-g3 5.nPg3-g2 6.nPg2-g1=nB 7.nBg1-d4 8.nBd4-h8 Gb2-b8 #

b) 1.nPh7-h5 2.nPh5-h4 3.nPh4-h3 4.nPh3-h2 5.nPh2-h1=nB 6.nBh1*b7 [+wPc8=wG] 7.nBb7-d5 8.nBd5-g8 Gc8-h8 #

  • CousCous Circe: when a capture is made, the captured unit (not a King) is replaced on the capturing unit’s rebirth square (according to Circe) if it is empty; otherwise the captured unit vanishes. For captures resulting in promotion, the promotion type is chosen by the side whose pawn promotes.
  • Change of function.