ChessProblems.ca Originals

2011 Tourney: T51-60

Compositions:
Main Page | T1-10 | T11-20 | T21-30 | T31-40 | T41-50 | T61-70 | T71-80
HC1-10 | HC11-20 | HC21-30 | HC31-40 | HC41-50 | HC51-60 | HC61-70

Last updated: 27.02.2012
# Problem Solution
T60 Ivan Skoba, Czech Republic
T60 ChessProblems.ca, 22.08.2011
serc-!= 45 (6+12)
Madrasi
Consequent


  • Withdrawn by the author.
T59 Uwe Mehlhorn
Germany
T59 ChessProblems.ca, 03.08.2011
6b1/4k3/7Q/8/8/8/2K5/8
ser-h= 7 (2+2) C+
Duplex


Solutions:

1.Bg8-e6 2.Ke7-d6 3.Kd6-c5 4.Kc5-b4 5.Kb4-a3 6.Ka3-a2 7.Ka2-a1 Qh6*e6 =

1.Kc2-d3 2.Kd3-e4 3.Ke4-f5 4.Kf5-g6 5.Kg6-g7 6.Kg7-h8 7.Qh6-f8 + Ke7*f8 =
  • New Wenigsteiner Series Helpstalemate Duplex length record. Previous record:
Unto Heinonen, A7 Problemkiste 01/2010
8/7Q/5k2/8/8/8/8/1b1K4
ser-h= 6 (2+2) C+
Duplex
1.Kf6-e5 2.Ke5-d4 3.Kd4-c3 4.Kc3-b2 5.Kb2-a1 6.Bb1-c2 + Qh7*c2 =

1.Kd1-e2 2.Ke2-f3 3.Kf3-g4 4.Kg4-h5 5.Kh5-h6 6.Qh7-g6 + Bb1*g6 =

T58 George P. Sphicas, USA
T58 ChessProblems.ca, 11.07.2011
8/8/8/3p4/R1R5/3p4/3pp2K/1k6
ser-hxz 15 (3+5) C+


Solution: 

1.d2-d1=R 2.Rd1-d2 3.Rd2-a2 4.d3-d2 5.d2-d1=Q 6.Qd1-d4 7.Qd4-a1 8.d5-d4 9.d4-d3 10.d3-d2 11.d2-d1=S 12.Sd1-b2 13.e2-e1=B 14.Be1-b4 15.Bb4-a3 Ra4-b4 xz
  • Light position with CapZug AUW!
T57 Dan Meinking, USA
T57 ChessProblems.ca, 21.06.2011

Position a:
8/8/8/8/2K5/8/2P1pp2/5k2
Position b:
8/8/8/8/2K5/8/2Q1nn2/5k2
phser-a=>b 16 (2+3) C+




Solution: 

1.Kd5! 6.c8Q 7.Qh3+! Ke1 8.Qh1+ f1S 9.Qh4+ Sg3 10.Qb4+ Kf1 11.Qb1+ e1S 12.Qb5+ Sd3 13.Kc4! 14.Qf5+ Sf2 15.Qd3+ Se2 16.Qc2 a=>b
  • Switchbacks by both Kings, Platzwechsel by the bP/bS pair, and 14-point no-repeat capture-free rundlauf by the wP/wQ!
  • Author's second shape-to-shape transformation using Parry Series. See the first one on the MatPlus.net Forum.
T56 Frank Müller & Uwe Mehlhorn
Germany
T56 ChessProblems.ca, 10.04.2011
8/8/6k1/8/8/8/8/7K
ser-sZh5 10 (1+1) C+
Sentinels


Solution:

1.Kh1-g2 2.Kg2-f3[+wPg2] 3.Kf3-e4[+wPf3] 4.Ke4-d5[+wPe4] 5.Kd5-d6[+wPd5] 6.Kd6-e7[+wPd6] 7.Ke7-f8[+wPe7] 8.e7-e8=R 9.Re8-e5 10.Re5-h5[+wPe5] Kg6*h5[+bPg6] z
  • Series self-targetsquare with Kings only.
  • Sentinels: On moving, a piece leaves behind a pawn of its own colour on its departure square. The rule does not apply to pawns, or to moves from the 1st or 8th rank; nor does it apply if there are 8 pawns of that colour already on the board.
  • By the same authors:
421 mpk-Blätter 04/2011
8/8/8/8/8/8/2k5/K7
ser-sZb3 11 (1+1) C+
Sentinels
1.Ka1-a2 2.Ka2-a1[+wPa2] 3.a2-a4 4.a4-a5 5.a5-a6 6.a6-a7 7.a7-a8=Q 8.Qa8-a7 9.Qa7-d4[+wPa7] 10.a7-a8=Q 11.Qa8-h1 Kc2-b3[+bPc2] z

T55 Dieter Müller & Arno Tüngler
Germany
T55 ChessProblems.ca, 10.04.2011
8/8/6B1/5n2/1Q2K1p1/3n1pPp/2k1pN1P/4R3
ser-h+z 3 (7+7)
4 solutions


Solutions:

1.Sd3-f4 2.Sf4-g2 3.Sg2-h4 Ke4-f4 +z
1.Sd3-e5 2.Se5-f7 3.Sf7-h8 Ke4-e5 +z
1.Sf5-d4 2.Sd4-b3 3.Sb3-a1 Ke4-d4 +z
1.Sf5-e3 2.Se3-f1 3.Sf1:h2 Ke4-e3 +z
  • All keys on the cross squares that the wK enters.
  • The first Series CheckZug! The concept is the same for all "Zug Family" relatives:

    The state of X-Zugzwang is reached when the side on move:

    (1) has one or more legal moves which achieve X; and
    (2) has no legal moves that fail to achieve X; and
    (3) is not in check

  • More details about the Zug Family on the Parry Series and Zug Family Hub.
T54 Guy Sobrecases & Arno Tüngler
France & Germany
T54 ChessProblems.ca, 10.04.2011
7k/8/8/8/6B1/8/pp1pp1Kp/2R5
pser-hxz 6 (6+3)
b) pser-h= 6



Solutions:

a) 1.h2-h1=Q + Kg2-f2 2.Qh1-g1 + Rc1*g1 3.e2-e1=R 4.Re1-a1 5.d2-d1=S + Bg4*d1 6.b2-b1=B Bd1-c2 xz

b) 1.d2-d1=S 2.Sd1-e3 + Kg2-g3 3.Se3-f5 + Bg4*f5 4.e2-e1=Q + Kg3*h2 5.Qe1-g1 + Rc1*g1 6.a2-a1=B Bf5-b1 =
  • In a) AUW, in b) three promotions with fine distinction between the two solutions - one with capture possibility for Black, one without!
  • Parry Series Help-CapZug in the diagram position and Parry Series Help-Stalemate in the twin!
  • Please note the new CapZug stipulation notation! More details about the Zug Family and the CapZug notation change on the Parry Series and Zug Family Hub, as outlined by the CapZug inventor, Dan Meinking.
T53 Mečislovas Rimkus
Lithuania
T53 ChessProblems.ca, 26.03.2011

ser-h# 10 (2+4) C+
b) wKg7-->c1
Double Grasshopper d5, e5, h1, h8


Solutions:

a) 1.DGh1-e8 2.Kd7-c6 3.DGd5-h7 4.DGe8-b7 5.Kc6-c5 6.DGe5-b8 7.Kc5-b6 8.Kb6-a7 9.Ka7-a8 10.DGh7-a7 Kg7-g8 #

b) 1.DGd5-c8 2.Kd7-c6 3.DGc8-f5 4.DGf5-b7 5.Kc6-d6 6.DGe5-a7 7.Kd6-c7 8.Kc7-b8 9.Kb8-a8 10.DGh1-b8 Kc1-b2 #

  • Double Grasshopper: Makes a Grasshopper move without capturing, then a 2nd Grasshopper move.
T52 Ján Golha
Slovakia
T52 ChessProblems.ca, 13.03.2011
After Jakob Mintz, IMR 1986
K6R/p4kQ1/b2p3p/3P3q/8/8/8/8
ser-h# 22 (4+6)




Solution:

1.K*g7 4.K*d5 5.Kc6 6.Qd5 11.h1R 13.Rb6 14.Bb5 19.a1S 22.Sd7 Rc8#

  • New ideal serieshelpmate length record - last move by Rook. The last 21 moves are C+.

    • On March 16th Vladimír Janál published on his blog the following new length record:
    5B2/8/1P1P1PP1/RB6/8/N2N1K1R/8/k7
    ser-h# 40 (11+1) C+
    7.Ke6*f6 8.Kf6*g6 10.Kf7*f8 13.Ke6*d6 18.Kb7*b6 19.Kb6*a5 27.Kb3*a3 35.Kb6*b5 37.Kc4*d3 40.Ke1-f1 Rh3-h1 #

  • April 10, 2011: the new record seats now at 51 moves! Please see HC51.
  • Table of records: lengthrecords.chessproblems.ca.
T51 Radovan Tomašević
Serbia
T51 ChessProblems.ca, 27.02.2011
nb5q/8/4pprp/3p4/2kP3p/1p3p1r/3P1P2/5Knb
ser-= 95 (4+15) C+



Solution:

10.Kb7*a8 16.Kf7*g6 30.Kf1*g1 47.Kg4*h3 48.Kh3*h4 65.Kg1*h1 83.Kg4*f3 84.Kf3-e3 87.f5*e6 89.e7-e8=R 90.Re8*h8 91.Rh8*h6 92.Rh6*f6 94.Rb6*b3 95.Rb3*b8 =