ChessProblems.ca Series-Movers Tourney


ChessProblems.ca organizes an annual Series-Movers Informal Tourney open for series-movers of any type and with any fairy conditions and pieces. Tasks and records are encouraged, but are not mandatory. Maximum four problems per author are accepted for the tourney (tournament entries are labeled "T[n]" in the table below), but compositions can also be sent for publication "hors concours" (labeled "HC[n]"). Please email your entries to Cornel Pacurar at originals (at) chessproblems.ca.

Judge for 2010:  Dan Meinking (USA)            |    2010 Award (16.05.2011)
Judge for 2011:  Paul Raican (Romania)
Judge for 2012:  Arno Tüngler (Germany)

Participants

# Composer Country 2010 2011 2012
1 Alberto Armeni Italy - 4 1
2 György Bakcsi Hungary 1 -  
3 Bojan Bašić Serbia 1 -  
4 Vlaicu Crişan Romania 0.5 -  
5 Mihail Croitor Moldova 1 -  
6 Itamar Faybish Belgium 0.5 -  
7 Geoff Foster Australia - 1  
8 Ján Golha Slovakia 1.5 2.5  
9 Harald Grubert Germany - 0.5  
10 Jozef Holubec Slovakia - 2  
11 Vladimír Janál Czech Republic 0.5 -  
12 Branko Koludrović Croatia 1 -  
13 Ralf Krätschmer Germany 1.5 -  
14 François Labelle Canada 0.5 -  
15 Alexandre Leroux Canada 0.5 -  
16 Uwe Mehlhorn Germany - 1.5  
17 Dan Meinking USA - 3.5  
18 Miodrag Mladenović Serbia 0.5 -  
19 Karol Mlynka Slovakia - 2  
20 Dieter Müller Germany - 1  
21 Frank Müller Germany - 0.5  
22 Ion Murăraşu Romania 1 - -
23 Cornel Pacurar Canada 3.5 3.5  
24 Paul Răican Romania 3 - 1
25 Mečislovas Rimkus Lithuania - 3.5 1
26 Zoran Sibinović Serbia 4 4  
27 Ivan Skoba Czech Republic 1.5 1.5 1
28 Guy Sobrecases France - 0.5  
29 George P. Sphicas USA 1 1  
30 Radovan Tomašević Serbia 2 3  
31 Arno Tüngler Germany 4 2.5 -

Compositions:
T1-10 | T11-20 | T21-30 | T31-40 | T41-50
HC1-10 | HC11-20 | HC21-30 | HC31-40 | HC41-50


Last updated: 26.01.2012
# Composition Solution
T76 Ivan Skoba
Czech Republic
T76 ChessProblems.ca, 26.01.2012
2r5/4r3/3K4/7R/4NkNb/7P/8/1bB4R ser-h# 215 (7+5) C+
Holes



Solution: 


7.Kd8 9.Rg8 11.Kf8 13.Re7 23.Ka1 24.Ba2 26.K*c1 28.Ka1 29.Bb1 39.Kf8 41.Rc8 43.Kd8 45.Re7 52.Kf4 55.Bg1 62.Kd8 64.Rg8 66.Kf8 68.Re7 78.Ka1 79.Ba2 86.K*h1 93.Ka1 94.Bb1 104.Kf8 106.Rc8 108.Kd8 110.Re7 117.Kf4 120.Bh4 127.Kd8 129.Rg8 131.Kf8 133.Re7 143.Ka1 144.Ba2 151.K*h3 158.Ka1 159.Bb1 169.Kf8 171.Rc8 173.Kd8 175.Re7 182.Kf4 185.Bg1 192.Kd8 194.Rg8 196.Kf8 198.Re7 208.Ka1 209.Ba2 215.Kg2 Se3 #

  • Pendulum of black King passing Zeller and Bishop traps. The entry tries to introduce basic series-mover manoeuvres that allow composing long problems. By using holes, the construction becomes very simple and light. We should also notice that the solution has twice 60 or more moves without capture!
T75 Alberto Armeni
Italy
T75 ChessProblems.ca, 26.01.2012
r5b1/8/4rP2/5P2/2P1N3/bpnP1p2/1np1pP2/1k2K3 ser-h== 12 (7+11) C?
Einstein Chess


Solution: 


1.R*f6=Q 2.B*c4=R 3.Rc-c8=B 4.B*f5=R 5.Rb5=B 6.B*d3=R 7.Rd1=B 8.Sd3=P 9.Bc1=S 10.Ra1=B 11.S3-a2=P 12.Qb2=R Sd2=P ==

  • Nice double-stalemate finale!
T74 Paul Răican
Romania
T74 ChessProblems.ca, 26.01.2012
8/1pp2r2/3b4/1pnk2rp/2pp4/Pp3nPp/1P3K2/5N2 ser-sxz 41 (5+14) C+
Isardam


Solution: 


5.Kb4*b5 7.a4-a5 14.Ke8*f7 26.Ke2*f3 29.Sg4-e5 31.Kf4*g5 32.Kg5*h5 37.g7-g8=R 39.Rg3*b3 40.Rb3-c3 41.b2-b4 c4*b3 ep. x

  • The first Series Self-Cap-Zug Isardam!
  • Isardam ("Madrasi" spelled backwards) is a variant of Madrasi in which only moves that do not lead to a Madrasi paralysis are legal.
  • C+ Popeye v4.55
HC55 Cornel Pacurar
Canada
HC55 ChessProblems.ca, 07.01.2012
8/8/1P6/8/8/1k1p4/3P4/K7
ser-r+ 20 (3+2) C+



Solution: 

9.Kc5-b5 11.b7-b8=S 12.Kb5-c5 14.Sa6-b4 19.Ke1-d1 20.Sb4-c2 d3*c2 +

  • New series reflex-check length record for 5 units.

Also, a new series reflex-check length record for 6 units:

Cornel Pacurar
HC56 ChessProblems.ca, 07.01.2012 8/8/1P6/8/8/1k1p4/3P4/rK6
ser-r+ 21 (3+3) C+
1.Kb1*a1 10.Kc5-b5 12.b7-b8=S 13.Kb5-c5 15.Sa6-b4 20.Ke1-d1 21.Sb4-c2 d3*c2 +

Previous record:

M. Tomašević
K177 Problemkiste (122) 04/1999 8/8/8/5p2/8/2p2k2/2P5/1BK5
ser-r+ 20 (3+3) C+
12.Kd4*c3 13.Kc3-d3 18.c7-c8=S 20.Sd6-e4 f5*e4 +
T73 Mečislovas Rimkus
Lithuania
T73 ChessProblems.ca, 07.01.2012
k5K1/1r6/P7/8/8/1p6/7P/r7 ser-s# 14 (3+4) C+
GhostChess



Solution: 


5.h7-h8=R 7.Rh7*b7 12.Kc4*b3 13.Kb3-b2[+buPb3] 14.Kb2*a1 uPb3-b2 #


T72 Arno Tüngler
Germany
T72 ChessProblems.ca, 26.12.2011
8/pp5p/P7/kB6/P7/2KQ4/PNP5/bR5B ser-h!= 30 (10+5) C+
VerticalMirrorCirce



Solution: 


4.h3-h2 5.b7*a6 6.a6*b5 [+wBc1] 7.b5*a4 9.a3*b2 12.Ka3*a2 16.Ka5-b6 21.a2*b1=B 22.Bb1*c2 [+wPf2] 23.Bc2*d3 [+wQe1] 25.Be4*h1 26.Bh1-f3 27.h2-h1=R 28.Rh1*e1 29.Re1-f1 30.b2*c1=Q + Kc3-d3 !=

  • Excelsior x 3 (BQR)!
T71 Ján Golha & Cornel Pacurar
Slovakia & Canada
T71 ChessProblems.ca, 19.12.2011
8/8/8/8/8/2Nk4/8/3B4 ser-h= 8 (2+1) C+
EquipollentsCirce
b) bKc4-->h1
c) bKc4-->d7
d) wBd6-->g3


Solutions: 

a)
1.Kc4-d3 2.Kd3*e4 [+wSf5] 3.Ke4*f5 [+wSg6] 4.Kf5-g5 5.Kg5-h6 6.Kh6*g6 [+wSf6] 7.Kg6-g7 8.Kg7-h8 Bd6-f8 =

b) bKc4->h1
1.Kh1-g2 2.Kg2-f3 3.Kf3*e4 [+wSd5] 4.Ke4*d5 [+wSc6] 5.Kd5*d6 [+wBd7] 6.Kd6-c7 7.Kc7-b7 8.Kb7-a8 Bd7-c8 =

c) bKc4->d7
1.Kd7-e6 2.Ke6-f5 3.Kf5*e4 [+wSd3] 4.Ke4-e3 5.Ke3*d3 [+wSc3] 6.Kd3-c2 7.Kc2-b2 8.Kb2-a1 Bd6-a3 =

d) wBd6->g3
1.Kc4-d4 2.Kd4*e4 [+wSf4] 3.Ke4-f3 4.Kf3*g3 [+wBh3] 5.Kg3*f4 [+wSe5] 6.Kf4-g3 7.Kg3-h2 8.Kh2-h1 Se5-f3 =

  • Wenigsteiner, 4-corner echoes.
  • No white King.
  • Version 20.12.2011.
T70 Cornel Pacurar
Canada
T70 ChessProblems.ca, 19.12.2011
8/3b4/8/3K4/k7/8/6P1/8 pser-h= 8 (2+2) C+
ParrainCirce, BrunnerChess
2 Solutions



Solutions: 


1.Ka4-b5 2.Kb5-c6 + Kd5-e4 3.Bd7-f5 + Ke4*f5 4.Kc6-d5 [+bBg4] + Kf5*g4 5.Kd5-e4 [+bBh3] + Kg4-f3 + 6.Bh3*g2 + Kf3*e4 [+wPf3] 7.Bg2-h1 8.Bh1*f3 + Ke4*f3 [+wPg2] =


1.Bd7-f5 2.Bf5-e4 + Kd5*e4 3.Ka4-b3 [+bBf3] + g2*f3 4.Kb3-c4 [+bBg4] 5.Bg4*f3 + Ke4-d3 [+wPe2] + 6.Bf3*e2 + Kd3*c4 [+wPd3] 7.Be2-f1 8.Bf1*d3 + Kc4*d3 [+wPe2] =

  • Wenigsteiner Parry-Series echoes.
HC54 Arno Tüngler
Germany
HC54 ChessProblems.ca, 12.12.2011
8/8/5K2/8/8/2B5/N1kN4/8
ser-h= 27 (4+1) C+
Vertical Mirror Circe


Solution: 

1.Kc2-d3 2.Kd3-e3 3.Ke3-f4 4.Kf4-g4 5.Kg4-h5 6.Kh5-h6 7.Kh6-h7 8.Kh7-g8 9.Kg8-f8 10.Kf8-e8 11.Ke8-d7 12.Kd7-c6 13.Kc6-b5 14.Kb5-a4 15.Ka4-a3 16.Ka3*a2 [+wSg1] 17.Ka2-a3 18.Ka3-a4 19.Ka4-b5 20.Kb5-c6 21.Kc6-d7 22.Kd7-e8 23.Ke8-f8 24.Kf8-g8 25.Kg8-h7 26.Kh7-h6 27.Kh6-h5 28.Kh5-g4 29.Kg4-f4 30.Kf4-e3 31.Ke3-d3 32.Kd3*c3 [+wBf1] 33.Kc3-d4 34.Kd4-e3 35.Ke3-f2 36.Kf2*g1 [+wSb1] 37.Kg1-h1 Sd2-f3 =

  • Serieshelpstalemate Vertical Mirror Circe move-length record for 5 units.
HC53 Arno Tüngler
Germany
HC53 ChessProblems.ca, 12.12.2011
7B/8/8/8/7k/1N3K2/8/8
ser-h= 27 (3+1) C+
Vertical Mirror Circe


Solution: 

1.Kh4-g5 2.Kg5-f5 3.Kf5-e6 4.Ke6-d5 5.Kd5-c4 6.Kc4*b3 [+wSg1] 7.Kb3-c4 8.Kc4-d5 9.Kd5-e6 10.Ke6-f7 11.Kf7-g8 12.Kg8*h8 [+wBf1] 13.Kh8-g7 14.Kg7-f6 15.Kf6-e5 16.Ke5-d4 17.Kd4-c3 18.Kc3-d2 19.Kd2-e1 20.Ke1*f1 [+wBc1] 21.Kf1*g1 [+wSb1] 22.Kg1-f1 23.Kf1-e1 24.Ke1-d1 25.Kd1*c1 [+wBf1] 26.Kc1-d1 27.Kd1-e1 Bf1-e2 =

  • Serieshelpstalemate Vertical Mirror Circe move-length record for 4 units.
T69 Mečislovas Rimkus
Lithuania
T69 ChessProblems.ca, 11.12.2011
4k3/8/3Kp3/8/7P/8/8/8 ser-h# 7 (2+2) C+
Take & Make Chess, Ghost Chess
b) wKd6->g6



Solutions: 

a)

5.e2-e1Q 6.Qe1xh4=Qh5 (gPh4) 7.Qh5-g5 gPh4xg5=g8Q (gQg5) #

b) wKd6->g6

5.e2-e1B 6.Be1-d2 7.Bd2-g5 h4xg5=Qd8 (gBg5) #
T68 Ivan Skoba & Arno Tüngler
Czech Republic & Germany
T68 ChessProblems.ca, 28.10.2011
4k3/1p4K1/8/8/8/8/2P5/8 pser-h= 12 (2+2) C+
Vertical Mirror Circe
b) wKg7->a5



Solutions: 

a)

1.b7-b5 2.b5-b4 3.b4-b3 4.b3*c2 [+wPf2] 5.c2-c1=Q 6.Qc1-g1 + Kg7-f6 7.Qg1-g6 + Kf6-e5 8.Qg6-g3 + f2-f4 9.Qg3-g5 + f4-f5 10.Qg5-g7 + f5-f6 11.Qg7-c7 + Ke5-e6 12.Qc7-e7 + f6*e7 =

b) wKg7->a5

1.b7-b6 + Ka5*b6 [+bPg7] 2.g7-g5 3.g5-g4 4.g4-g3 5.g3-g2 6.g2-g1=Q + Kb6-c6 7.Qg1-b6 + Kc6-d5 8.Qb6-b3 + c2-c4 9.Qb3-b5 + c4-c5 10.Qb5-b7 + c5-c6 11.Qb7-d7 + c6*d7 + 12.Ke8-d8 Kd5-d6 =

  • Parry-Series Wenigsteiner and chameleon-echoes.
  • For a few more Vertical Mirror Circe Parry-Series please see ifaybish.com TT7 tourney results.
T67 Alberto Armeni, Italy
T67 ChessProblems.ca, 11.10.2011
4N2k/5p2/8/p7/2pNP1pr/6p1/6P1/3Kb2n ser-= 10 (5+9) C+
Einstein Chess

Solution: 

1.Sd4-b3=P 2.b3*c4=S 3.Sc4*a5=B 4.Ba5*e1=R 5.Re1*h1=Q 6.Qh1-e1=R 7.Re1-e2=B 8.Be2-f3=S 9.Sf3*h4=B 10.Bh4-f6=S =
  • Again the full spectrum of Einstein transformations!
HC52 Ivan Skoba
Czech Republic
HC52 ChessProblems.ca, 11.10.2011

Position a:
6r1/3p4/rn3P2/1pbp1p2/1P1p4/np1k4/3P2Bq/3KB2r

Position b:
6r1/3p4/1n3P2/2bp1p2/1P1p4/1p1k4/3P2Bq/3KB2r
ser-a=>b 112 (6+14)/(6+11) C+





Solution: 

2.Kc1-b2 4.Bf2-g1 9.Kf2-f3 11.Bf2-g3 12.Kf3-f4 15.Bh5-g6 16.Kf4-g5 20.Bg6-e8 22.Kg6-f7 24.Bf8-d6 29.Kb7*a6 34.Ke7-f7 36.Bf8-g7 38.Kg6-g5 42.Bd6-g3 43.Kg5-f4 46.Bf3-g2 47.Kf4-f3 49.Bf2-g1 55.Kb2*a3 61.Kf2-f3 63.Bf2-g3 64.Kf3-f4 67.Bh5-g6 68.Kf4-g5 72.Bg6-e8 74.Kg6-f7 76.Bf8-d6 82.Ka6*b5 88.Ke7-f7 90.Bf8-g7 92.Kg6-g5 96.Bd6-g3 97.Kg5-f4 100.Bf3-g2 101.Kf4-f3 103.Bf2-g1 108.Kc1-b2 110.Bf2-e1 112.Kc1-d1 a=>b

T66 Dan Meinking, USA
T66 ChessProblems.ca, 12.09.2011
pser-h# 5 (2+2) C+
Orphan h1
b) bKg4->b4
c) wKb2->g6

Solutions: 

a)

1.d2-d1=S + Kb2-c2 2.Sd1-e3 + Kc2-d2 3.Se3-f1 + Kd2-e2 4.Sf1-g3 + Ke2-f2 5.Kg4-h3 Oh1*g3 #

b) bKg4->b4

1.d2-d1=R 2.Rd1-b1 + Kb2-c2 3.Kb4-a3 4.Ka3-a2 5.Ka2-a1 Oh1*b1 #

c) wKb2->g6

1.d2-d1=Q 2.Qd1-b1 + Oh1-e4 + 3.Qb1-g1 4.Kg4-h4 + Kg6-f5 5.Qg1-g4 + Oe4*g4 #

  • Wenigsteiner, three promotions and nice Orphan chameleon-echoes.
  • The second Parry-Series employing an Orphan (the first being: Cornel Pacurar, F471 Problem Paradise, 2010).
T65 Dan Meinking, USA
T65 ChessProblems.ca, 12.09.2011
pser-h= 11 (2+2) C+
Take & Make Chess, PWC
b) wKd1->f2

Solutions: 

a)

1.Ke4-e3 2.Ke3-f2 3.Kf2*e2-e4 [+wPf2] 4.Ke4-f3 5.e5-e4 6.e4-e3 7.e3-e2 + Kd1-d2 8.e2-e1=Q + Kd2-d3 9.Qe1-e3 + f2*e3-e8=Q [+bQf2] 10.Qf2-f1 + Qe8-e2 + 11.Kf3*e2-e1 [+wQf3] + Qf3*f1-f3 =

b) wKd1->f2

1.Ke4-d4 2.Kd4-c3 3.Kc3-d2 4.Kd2*e2-e4 [+wPd2] 5.Ke4-f4 6.e5-e4 7.e4-e3 + Kf2*e3-e2 [+bPf2] 8.f2-f1=Q + Ke2*f1-g1 [+bQe2] 9.Qe2-e3 + d2*e3-e8=Q [+bQd2] 10.Qd2-d4 + Qe8-e3 + 11.Kf4*e3-h3 [+wQf4] + Qf4*d4-f4 =

  • Chris Feather and Geoff Foster have recently published nine Take&Make + PWC series-helpmates in a special issue of Fairings (15b) - this is a first Parry-Series Take&Make + PWC!
  • Wenigsteiner.
T64 Dan Meinking & Cornel Pacurar, USA & Canada
T64 ChessProblems.ca, 25.08.2011
pser-hs# 7 (2+2) C+
Princess c6
Andernach Grasshopper h3
b) wPRc6->c5

Solutions: 

a)

1.Kg5-h5 2.AGh3-h6 3.AGh6-b6 [bPRc6] 4.PRc6-d4 + Kf2-g2 5.PRd4-e3 + Kg2-h3 6.AGb6-f2 [wPRe3] PRe3-f4 + 7.AGf2-f5 [bPRf4] #

b) wPRc6->c5

1.Kg5-h4 2.AGh3-h5 3.AGh5-b5 [bPRc5] + Kf2-f1 4.PRc5-d3 + Kf1-g1 5.PRd3-e2 + Kg1-h2 6.AGb5-f1 [wPRe2] PRe2-f3 + 7.AGf1-f4 [bPRf3] #

  • Wenigsteiner, Chameleon Echoes, Parry-Series Help-Selfmate.
T63 Cornel Pacurar, Canada
T63 ChessProblems.ca, 25.08.2011
pser-hs# 5 (2+2) C+
Isardam
2 Solutions
b) wKd3->e2

Solutions: 

a)

1.Kf5-f6 2.Qg5-d2 + Kd3-e4 3.Qd2-g2 + Qb8-e5 + 4.Qg2-g7 Ke4-f5 + 5.Qg7-g5 #

1.Kf5-f4 2.Qg5-g3 + Kd3-d4 3.Qg3-f2 + Qb8-e5 4.Qf2-g3 Kd4-e4 + 5.Qg3-e3 #

b) wKd3->e2

1.Qg5-d2 + Ke2-f3 2.Qd2-d5 + Qb8-f4 3.Kf5-e5 4.Qd5-d6 Kf3-e4 + 5.Qd6-d4 #

1.Qg5-g4 + Ke2-f2 2.Qg4-d4 + Qb8-g3 3.Kf5-f4 4.Qd4-e5 Kf2-f3 + 5.Qe5-e3 #

  • Wenigsteiner, Echoes, Parry-Series Help-Selfmate.
T62 Geoff Foster, Australia
T62 ChessProblems.ca, 22.08.2011
ser-h# 8 (2+1) C+
PWC, Take & Make Chess
Lion b6
2 Solutions
b) wLIb6->g6

Solutions: 

a)

1.Ke8*f8-d7 [+wSe8] 2.Kd7*e8-d6 [+wSd7] 3.Kd6*d7-c5 [+wSd6] 4.Kc5*b6-e6 [+wLIc5] 5.Ke6-d5 6.Kd5*c5-e7 [+wLId5] 7.Ke7*d6-b7 [+wSe7] 8.Kb7-a8 Se7-c6 #

1.Ke8-e7 2.Ke7*f8-e6 [+wSe7] 3.Ke6*e7-d5 [+wSe6] 4.Kd5*e6-d4 [+wSd5] 5.Kd4*d5-c7 [+wSd4] 6.Kc7-b7 7.Kb7*b6-g1 [+wLIb7] 8.Kg1-h1 Sd4-f3 #

b) wLIb6->g6

1.Ke8*f8-d7 [+wSe8] 2.Kd7*e8-d6 [+wSd7] 3.Kd6*d7-e5 [+wSd6] 4.Ke5*d6-e4 [+wSe5] 5.Ke4*e5-f7 [+wSe4] 6.Kf7-g7 7.Kg7*g6-b1 [+wLIg7] 8.Kb1-a1 Se4-c3 #

1.Ke8-e7 2.Ke7*f8-e6 [+wSe7] 3.Ke6*e7-f5 [+wSe6] 4.Kf5*g6-d6 [+wLIf5] 5.Kd6-e5 6.Ke5*f5-d7 [+wLIe5] 7.Kd7*e6-g7 [+wSd7] 8.Kg7-h8 Sd7-f6 #

  • Beautiful 4-corner echoes!
T61 Ivan Skoba, Czech Republic
T61 ChessProblems.ca, 22.08.2011
serc-!= 75 (8+10)
Madrasi
Consequent


Solution: 

See the solution and detailed explanation, as received from the author, here.
  • An interesting interpretation of the Series Consequent genre! More details will be posted soon.
T60 Ivan Skoba, Czech Republic
T60 ChessProblems.ca, 22.08.2011
serc-!= 45 (6+12)
Madrasi
Consequent


  • Withdrawn by the author.
T59 Uwe Mehlhorn
Germany
T59 ChessProblems.ca, 03.08.2011
6b1/4k3/7Q/8/8/8/2K5/8
ser-h= 7 (2+2) C+
Duplex


Solutions:

1.Bg8-e6 2.Ke7-d6 3.Kd6-c5 4.Kc5-b4 5.Kb4-a3 6.Ka3-a2 7.Ka2-a1 Qh6*e6 =

1.Kc2-d3 2.Kd3-e4 3.Ke4-f5 4.Kf5-g6 5.Kg6-g7 6.Kg7-h8 7.Qh6-f8 + Ke7*f8 =
  • New Wenigsteiner Series Helpstalemate Duplex length record. Previous record:
Unto Heinonen, A7 Problemkiste 01/2010
8/7Q/5k2/8/8/8/8/1b1K4
ser-h= 6 (2+2) C+
Duplex
1.Kf6-e5 2.Ke5-d4 3.Kd4-c3 4.Kc3-b2 5.Kb2-a1 6.Bb1-c2 + Qh7*c2 =

1.Kd1-e2 2.Ke2-f3 3.Kf3-g4 4.Kg4-h5 5.Kh5-h6 6.Qh7-g6 + Bb1*g6 =

T58 George P. Sphicas, USA
T58 ChessProblems.ca, 11.07.2011
8/8/8/3p4/R1R5/3p4/3pp2K/1k6 ser-hxz 15 (3+5) C+


Solution: 

1.d2-d1=R 2.Rd1-d2 3.Rd2-a2 4.d3-d2 5.d2-d1=Q 6.Qd1-d4 7.Qd4-a1 8.d5-d4 9.d4-d3 10.d3-d2 11.d2-d1=S 12.Sd1-b2 13.e2-e1=B 14.Be1-b4 15.Bb4-a3 Ra4-b4 xz
  • Light position with CapZug AUW!
T57 Dan Meinking, USA
T57 ChessProblems.ca, 21.06.2011

Position a:
8/8/8/8/2K5/8/2P1pp2/5k2
Position b:
8/8/8/8/2K5/8/2Q1nn2/5k2
phser-a=>b 16 (2+3) C+




Solution: 

1.Kd5! 6.c8Q 7.Qh3+! Ke1 8.Qh1+ f1S 9.Qh4+ Sg3 10.Qb4+ Kf1 11.Qb1+ e1S 12.Qb5+ Sd3 13.Kc4! 14.Qf5+ Sf2 15.Qd3+ Se2 16.Qc2 a=>b
  • Switchbacks by both Kings, Platzwechsel by the bP/bS pair, and 14-point no-repeat capture-free rundlauf by the wP/wQ!
  • Author's second shape-to-shape transformation using Parry Series. See the first one on the MatPlus.net Forum.
HC51 Zoran Sibinović
Serbia
HC51 ChessProblems.ca, 10.04.2011
1NB5/2p5/2P2K1k/BR1P3Q/1P6/1R1N2P1/3PP1P1/8
ser-h# 51 (15+2) C+



Solution: 

1.Kh6*h5 8.Kd8*c8 17.Kg4*g3 18.Kg3*g2 20.Kf1*e2 21.Ke2*d2 25.Kc4*b5 27.Kc4*d5 39.Kc8*b8 43.Kb5*c6 44.Kc6-d6 47.c4*d3 49.d2-d1=R 51.Rc1-c6 Rb3-d3 #

  • New ideal serieshelpmate length record - last move by Rook.
  • For previous record see T52.
  • 01.06.2011: New record by Vladimír Janál - 54 moves
T56 Frank Müller & Uwe Mehlhorn
Germany
T56 ChessProblems.ca, 10.04.2011
8/8/6k1/8/8/8/8/7K
ser-sZh5 10 (1+1) C+
Sentinels


Solution:

1.Kh1-g2 2.Kg2-f3[+wPg2] 3.Kf3-e4[+wPf3] 4.Ke4-d5[+wPe4] 5.Kd5-d6[+wPd5] 6.Kd6-e7[+wPd6] 7.Ke7-f8[+wPe7] 8.e7-e8=R 9.Re8-e5 10.Re5-h5[+wPe5] Kg6*h5[+bPg6] z
  • Series self-targetsquare with Kings only.
  • Sentinels: On moving, a piece leaves behind a pawn of its own colour on its departure square. The rule does not apply to pawns, or to moves from the 1st or 8th rank; nor does it apply if there are 8 pawns of that colour already on the board.
  • By the same authors:
421 mpk-Blätter 04/2011
8/8/8/8/8/8/2k5/K7
ser-sZb3 11 (1+1) C+
Sentinels
1.Ka1-a2 2.Ka2-a1[+wPa2] 3.a2-a4 4.a4-a5 5.a5-a6 6.a6-a7 7.a7-a8=Q 8.Qa8-a7 9.Qa7-d4[+wPa7] 10.a7-a8=Q 11.Qa8-h1 Kc2-b3[+bPc2] z

T55 Dieter Müller & Arno Tüngler
Germany
T55 ChessProblems.ca, 10.04.2011
8/8/6B1/5n2/1Q2K1p1/3n1pPp/2k1pN1P/4R3
ser-h+z 3 (7+7)
4 solutions


Solutions:

1.Sd3-f4 2.Sf4-g2 3.Sg2-h4 Ke4-f4 +z
1.Sd3-e5 2.Se5-f7 3.Sf7-h8 Ke4-e5 +z
1.Sf5-d4 2.Sd4-b3 3.Sb3-a1 Ke4-d4 +z
1.Sf5-e3 2.Se3-f1 3.Sf1:h2 Ke4-e3 +z
  • All keys on the cross squares that the wK enters.
  • The first Series CheckZug! The concept is the same for all "Zug Family" relatives:

    The state of X-Zugzwang is reached when the side on move:

    (1) has one or more legal moves which achieve X; and
    (2) has no legal moves that fail to achieve X; and
    (3) is not in check

  • More details about the Zug Family on the Parry Series and Zug Family Hub.
T54 Guy Sobrecases & Arno Tüngler
France & Germany
T54 ChessProblems.ca, 10.04.2011
7k/8/8/8/6B1/8/pp1pp1Kp/2R5
pser-hxz 6 (6+3)
b) pser-h= 6



Solutions:

a) 1.h2-h1=Q + Kg2-f2 2.Qh1-g1 + Rc1*g1 3.e2-e1=R 4.Re1-a1 5.d2-d1=S + Bg4*d1 6.b2-b1=B Bd1-c2 xz

b) 1.d2-d1=S 2.Sd1-e3 + Kg2-g3 3.Se3-f5 + Bg4*f5 4.e2-e1=Q + Kg3*h2 5.Qe1-g1 + Rc1*g1 6.a2-a1=B Bf5-b1 =
  • In a) AUW, in b) three promotions with fine distinction between the two solutions - one with capture possibility for Black, one without!
  • Parry Series Help-CapZug in the diagram position and Parry Series Help-Stalemate in the twin!
  • Please note the new CapZug stipulation notation! More details about the Zug Family and the CapZug notation change on the Parry Series and Zug Family Hub, as outlined by the CapZug inventor, Dan Meinking.
T53 Mečislovas Rimkus
Lithuania
T53 ChessProblems.ca, 26.03.2011

ser-h# 10 (2+4) C+
b) wKg7-->c1
Double Grasshopper d5, e5, h1, h8


Solutions:

a) 1.DGh1-e8 2.Kd7-c6 3.DGd5-h7 4.DGe8-b7 5.Kc6-c5 6.DGe5-b8 7.Kc5-b6 8.Kb6-a7 9.Ka7-a8 10.DGh7-a7 Kg7-g8 #

b) 1.DGd5-c8 2.Kd7-c6 3.DGc8-f5 4.DGf5-b7 5.Kc6-d6 6.DGe5-a7 7.Kd6-c7 8.Kc7-b8 9.Kb8-a8 10.DGh1-b8 Kc1-b2 #

  • Double Grasshopper: Makes a Grasshopper move without capturing, then a 2nd Grasshopper move.
T52 Ján Golha
Slovakia
T52 ChessProblems.ca, 13.03.2011
After Jakob Mintz, IMR 1986
K6R/p4kQ1/b2p3p/3P3q/8/8/8/8
ser-h# 22 (4+6)




Solution:

1.K*g7 4.K*d5 5.Kc6 6.Qd5 11.h1R 13.Rb6 14.Bb5 19.a1S 22.Sd7 Rc8#

  • New ideal serieshelpmate length record - last move by Rook. The last 21 moves are C+.

    • On March 16th Vladimír Janál published on his blog the following new length record:
    5B2/8/1P1P1PP1/RB6/8/N2N1K1R/8/k7
    ser-h# 40 (11+1) C+
    7.Ke6*f6 8.Kf6*g6 10.Kf7*f8 13.Ke6*d6 18.Kb7*b6 19.Kb6*a5 27.Kb3*a3 35.Kb6*b5 37.Kc4*d3 40.Ke1-f1 Rh3-h1 #

  • April 10, 2011: the new record seats now at 51 moves! Please see HC51.
  • Table of records: lengthrecords.chessproblems.ca.
T51 Radovan Tomašević
Serbia
T51 ChessProblems.ca, 27.02.2011
nb5q/8/4pprp/3p4/2kP3p/1p3p1r/3P1P2/5Knb
ser-= 95 (4+15) C+



Solution:

10.Kb7*a8 16.Kf7*g6 30.Kf1*g1 47.Kg4*h3 48.Kh3*h4 65.Kg1*h1 83.Kg4*f3 84.Kf3-e3 87.f5*e6 89.e7-e8=R 90.Re8*h8 91.Rh8*h6 92.Rh6*f6 94.Rb6*b3 95.Rb3*b8 =

Compositions:
T1-10 | T11-20 | T21-30 | T31-40 | T41-50
HC1-10 | HC11-20 | HC21-30 | HC31-40 | HC41-50